course Phy 241
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
First I found the area. 5.10 cm x 1.90 cm=about 9.69 cm^2. Then I thought you should find the minimum and maximum areas which would be 5.11 cm x 1.91 cm=9.7601 and 5.09cm x 1.89 cm= 9.6201. I thought that maybe it was plus or minus the difference between the max and min divided by two. This would yield .07, but then the question goes on to say that the fractional uncertainty is equal to the sum of the fractional uncertainties. I know the fractional uncertainty is a percentage, but I am not sure how to obtain it from the results I have, or if I am on the right track.
If you find the percent uncertainty in the 5.10 cm measurement, then the percent uncertainty in the 1.90 cm measurement, I believe you will get something like .2% and .5%, which would add up to .7%.
Half the difference between the two areas would be .14 cm^2. Half of this is .07 cm^2, which is .7% of the 9.7 cm^2 result.
So the sum of the uncertainties in the two measurements is equal to the uncertainty in their product.
Also on 1.12 we had to find a percent error. Is the equation for percent error the absolute value of the difference between the accepted value and the approximate value, then divided by the accepted value, then multiplied by 100?
That is correct.
`ex20
`ex21
course Phy 241
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
First I found the area. 5.10 cm x 1.90 cm=about 9.69 cm^2. Then I thought you should find the minimum and maximum areas which would be 5.11 cm x 1.91 cm=9.7601 and 5.09cm x 1.89 cm= 9.6201. I thought that maybe it was plus or minus the difference between the max and min divided by two. This would yield .07, but then the question goes on to say that the fractional uncertainty is equal to the sum of the fractional uncertainties. I know the fractional uncertainty is a percentage, but I am not sure how to obtain it from the results I have, or if I am on the right track.
If you find the percent uncertainty in the 5.10 cm measurement, then the percent uncertainty in the 1.90 cm measurement, I believe you will get something like .2% and .5%, which would add up to .7%.
Half the difference between the two areas would be .14 cm^2. Half of this is .07 cm^2, which is .7% of the 9.7 cm^2 result.
So the sum of the uncertainties in the two measurements is equal to the uncertainty in their product.
Also on 1.12 we had to find a percent error. Is the equation for percent error the absolute value of the difference between the accepted value and the approximate value, then divided by the accepted value, then multiplied by 100?
That is correct.
`ex20
`ex21