Determine the acceleration of an object whose velocity is initially 22 cm/s and which accelerates uniformly through a distance of 49 cm in 3.4 seconds. First we can find the average velocity by taking `ds/`dt. This equals about 14 cm/s. Then we can find the final velocity by knowing that the average velocity is equal to the initial velocity plus the final velocity over 2. Rearranging this equation and solving for Vf yields about 6.8 cm/sec. Now that we have both the initial and final velocity we can find `dv. `dv=Vf-V0. This equals about -15 cm/s. Divide `dv by `dt to obtain acceleration. The acceleration is about -4.5 cm/s^2. "