course Phy 241
An object is given an unknown initial velocity up a long ramp on which its acceleration is known to have magnitude 13 cm/s^2. .179 seconds later it passes a point 5 cm up the ramp from its initial position. •What are its possible initial velocities, and what is a possible scenario for each?
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• What is the maximum distance the object travels up the ramp?
The average velocity can first be found by taking 5 cm and dividing by .179 seconds to yield 27.9 seconds. If a=`dv/`dt then `dv must equal 13*.179 or 2.327. Vf and V0 are unknowns so we can use the fact that Vf-V0=2.327 and let Vf=V0+2.327. Then we can plug that into the equation (Vf+v0)/2 to equal 27.9. Therefore the equation to solve for V0 looks like {(2.327 +V0)+v0}/2=27.9. Solve for v0 to obtain 26.7 cm/s.
If the acceleration is constant along the ramp, the maximum distance gone would be the distance of the ramp.
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