Assignment 9

course mth 163

????????Sw?????assignment #009

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009.

Precalculus I

02-12-2007

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19:08:13

`q001. Note that this assignment has 2 questions

For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

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RESPONSE -->

In terms of x1 the coordinates:

(x1, 1.1x1+.8)

In terms of x2 the coordinates:

(x2. 1.1x2+.8)

Rise: (1.1x2 + .8) - (1.1x1 + .8)

Run: x2 - x1

Average slope: [(1.1x2 + .8) - (1.1x1 + .8)] / x2 - x1

(1.1x2 - 1.1x1) / (x2 - x1)

1.1 (x2 - x1) / (x2 - x1)

1.1

confidence assessment: 3

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19:08:31

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8).

The rise between the two points is therefore

rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1.

The run is

run = x2 - x1.

The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1.

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RESPONSE -->

self critique assessment: 3

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19:12:30

`q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

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RESPONSE -->

(x1, 3.4x1 + 7)

(x2, 3.4x2 + 7)

Rise: (3.4x2 + 7) - (3.4x1 + 7)

Run: x2 - x1

Average slope: [(3.4x2 + 7) - (3.4x1 + 7)] / x2 - x1

(3.4x2 - 3.4 x1) / x2 - x1

3.4

confidence assessment: 3

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19:12:36

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7).

The rise between the two points is therefore

rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1.

The run is

run = x2 - x1.

The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4.

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RESPONSE -->

self critique assessment: 3

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This looks good. Let me know if you have questions.