cq_1_072

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Phy 241

Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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cq_1_072

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Phy 241

Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest.

The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.

At what average rate is the automobile's acceleration changing with respect to the slope of the incline?

answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :

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'ds= 10 m

t = 8 s

v = 'ds/'dt

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With the notation we are using this would be vAve, not just v.

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= 10 m / 8 s

= 1.25 m/s

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1.25 m/s is vAve, not `dv.

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&&&& 'ds = 10m

t = 8 s

v_avg = 'ds/'dt

= 10m/8s

=1.25 m/s

a = 'dv / 'dt

= 2.5 m/s / 8s

= .3125 m/s^2

'ds = 10m

t=5s

v_avg = 'ds/'dt

= 10m/5s

= 2m/s

a = 'dv/'dt

= 4 m/s / 5s

= 0.8 m/s^2

'd(acceleration) / 'd(slope) = (a2 - a1)/ (slope2 - slope1)

= (0.8 m/s^2 - 0.3125 m/s^2) / (0.10 - 0.05)

= 9.75 m/s^2-slope

&&&&

a = 'dv/'dt

= 1.25 m/s / 8 s

= 0.15625 m/s^2

'ds = 10 m

t = 5 s

v = 'ds/'dt

= 10 m / 5 s

= 2 m/s

a = 'dv/'dt

= 2 m/s / 8 s

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The time interval on this ramp is 5 s, not 8 s.

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= 0.25 m/s^2

delta(a)/delta(slope) = (a_2 - a_1) / (slope_2 - slope_1)

= (0.25 m/s^2 - 0.156 m/s^2) / (0.10 - 0.05)

= 1.875 m/s^2-slope

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10 minutes

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&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).

Be sure to include the entire document, including my notes.

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How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :

v_5 = -25 m/s

v_6 = -35 m/s

After the 4th second its at the original starting point. After the 5th second it is at 25 m below the starting point and after the 6th second it is at 60 m below the starting point

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*#&!

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A couple of your results need to be modified.

&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).

Be sure to include the entire document, including my notes.

&#

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10 minutes

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resubmitted for your viewing pleasure

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It's always a pleasure to read a correct revision, as was the case here.

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