cq_1_101

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Phy 241

Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_10.1_labelMessages **

A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation

(extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point).

As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point)

is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.

How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium,

and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?

It takes approximately 1 second to go from one extreme point to the other.

It takes approximately 0.5 seconds to go from one extreme point to equilibrium.

It takes 1.5 secs to go from extreme point to equilibrium to opposite extreme point and back to equilibrium.

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answer/question/discussion: ->->->->->->->->->->->-> :

What reasonable assumption did you make to arrive at your answers?

I assumed that the amplitude is small compared to the length of the pendelum and there is no air resistance,

meaning the pendulums magnitude is constant.

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answer/question/discussion: ->->->->->->->->->->->-> :

@&

You also had to assume that the time from extreme position to equilibrium was equal to the time from equilibrium to extreme, and that four such intervals constitute a complete cycle.

These things are so obvious that few students even realize that the assumptions are being made.

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