course phy 231 Wȳc̍韪ڹassignment #000
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19:01:11 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> there is no discrepancies in the timer program. only human triggering. there is major discrepancy with human triggering. the speed at which one clicks can differ each time the trigger is clicked. the angle of the object plays a big role in the time it takes for it to get to the end of the incline. there is not much difference in the time it takes for an object to reach the same difference. it depends mostly on when the object is released and its positioning. there is of course a big discrepancy in observing. confidence assessment: 3
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19:14:11 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> there should be no uncertainty in the timer program. there is great uncertainty in the precision of human triggering. there should be no uncertainty in the time required for the object to travel the same distance. there is no uncertainty in the differences in the positioning of the object. as position can always change while going down the incline. thereis uncertainty in observing when the objecthas reached the end of the incline. confidence assessment: 3
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19:14:18 01-23-2008 19:14:18 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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19:31:40 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> the frequency would be slower if the length of the pendulum was doubled. so it would be less than half confidence assessment: 3
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19:35:06 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> point on the x axis has its y coordinate zero since the distance of this point from the x-axis is zero. and vice versa. so the origin is 0 confidence assessment: 3
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19:45:01 01-23-2008 19:45:01 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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assignment #000 000. `Query 0 Physics I 01-23-2008 wؼWz즖ڦ assignment #000 000. `Query 0 Physics I 01-23-2008
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21:09:44 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> doubling the length of the pendulum will slow the frequency.therby it would be lass than half confidence assessment: 3
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21:11:02 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> point on the x axis has its y coordinate zero since the distance of this point from the x-axis is zero. so its origin is 0 .(0,0) confidence assessment: 3
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21:20:19 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> it would mean that the frequency is increasing. on the graph. this would mean that as length increases, the frequency of the pendulum would decrease. confidence assessment: 2
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21:21:20 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> it would mean that as length increases, frequency decreases. confidence assessment: 2
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21:22:37 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> 1.2 cm confidence assessment: 2
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21:23:54 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> i should of multiplied time by distance., not divide. dividing these 2 would give me the average instead confidence assessment: 3
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21:24:46 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> confidence assessment: 0
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