assignment 6 query

course phy 231

ḇ؀ΨUQʆassignment #006

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006. `query 6

Physics I

02-06-2008

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assignment #006

006. `query 6

Physics I

02-06-2008

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21:01:49

univ 1.70 univ sailor 2 km east, 3.5 km SE, then unknown, ends up 5.8 km east find magnitude and direction of 3d leg, explain how diagram shows qualitative agreement

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RESPONSE -->

y = o

x = 5.8 km

a= 2

b= 315

a and b would be on the x axis. ax-bx-x

so 5.8- 2- 2.47 = 1.33

confidence assessment: 1

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21:02:07

** Letting the three vectors be A, B and C (C unknown) and the x axis point east we have A at 0 degrees, B at 315 degrees and the resultant at 0 degrees.

Ax = 2, Ay = 0 (A is toward the East, along the x axis).

Bx = B cos(315 deg) = 2.47, By = B sin(315 deg) = -2.47.

Rx = 5.8, Ry = 0.

Since Ax + Bx + Cx = Rx we have Cx = Rx - Ax - Bx = 5.8 - 2 - 2.47 = 1.33.

Since Ay + By + Cy = Ry we have Cy = Ry - Ay - By = 0 - 0 - (-2.47) = 2.47.

C has magnitude sqrt( Cx^2 + Cy^2) = sqrt ( 1.33^2 + 2.47^2) = sqrt(7.9) = 2.8, representing 2.8 km.

C has angle arctan(Cy / Cx) = arctan(2.47 / 1.33) = 61 deg. **

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RESPONSE -->

still learning about magnitudes

self critique assessment: 1

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In your self-critique you need a phrase-by-phrase analysis of the given solution, detailing everything you do and do not understand.

Deconstruct the given solution and explain in detail what you do and do not understand about every part.

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21:04:26

**** query univ 1.82 (1.66 10th edition) vectors 3.6 at 70 deg, 2.4 at 210 deg find scalar and vector product

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RESPONSE -->

2.4*3.6* cos *140 = -6.62

A * B = !A!!B! cos theta

confidence assessment: 1

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Your scalar product is good but you didn't do the vector product.

You should deconstruct the given solution and include a phrase-by-phrase interpretation of the given solution.