course MTH 158 should this be taking so long to finish. around 4 hours per section m???????????assignment #002
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13:40:17 R.2.90 (was R.4.36). Express (x^-2 y) / (x y^2) with only positive exponents and explain how you used the laws of exponents to get your result.
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RESPONSE --> I think this is the place i left off . (x^-2 y) / (x y^2) = (x^-2 / x)*(y / y^2) =(x^-2)^1 (y^1)^2 = x^-1 y^3 This is as far as i could get with the book. my brotherinlaw told me somthing to try so lets see (x^-2 y) / (x y^2) = (x^-2 y) / (x yy) = y / (xxx yy) = 1 / (x^3 y) confidence assessment: 2
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13:45:12 ** (1/x^2 * y) / (x * y^2) = (1/x^2 * y) * 1 / (x * y^2) = y * 1 / ( x^2 * x * y^2) = y / (x^3 y^2) = 1 / (x^3 y). Alternatively, or as a check, you could use exponents on term as follows: (x^-2y)/(xy^2) = x^-2 * y * x^-1 * y^-2 = x^(-2 - 1) * y^(1 - 2) = x^-3 y^-1 = 1 / (x^3 y).**
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RESPONSE --> I should have used the law a^-B = 1/a^B bUT I STILL GOT IT self critique assessment: 2
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14:29:18 Extra Problem. . Express 4 x^-2 (y z)^-1 / [ (-5)^2 x^4 y^2 z^-5 ] with only positive exponents and explain how you used the laws of exponents to get your result.
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RESPONSE --> 4 x^-2 (y z)^-1 / [ (-5)^2 x^4 y^2 z^-5 ] =ZZZZZ / 4 XXXXXX YYY Z 25 =Z^4/ 4*X^6*Y^3*25 confidence assessment: 2
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14:31:46 ** Starting with 4x^-2(yz)^-1/ [ (-5)^2 x^4 y^2 z^-5] Squaring the -5 and using the fact that (yz)^-1 = y^1 * z^-1: 4x^-2 * y^-1 * z^-1/ [25 * x^4 * y^2 * z^-5} Grouping the numbers, and the x, the y and the z expression: (4/25) * (x^-2/x^4) * (y^-1/y^2) * (z^-1/z^-5) Simplifying by the laws of exponents: (4/25) * x^(-2-4) * y^(-1-2) * z^(-1+5) Simplifying further: (4/25) * x^-6 * y^-3 * z^4 Writing with positive exponents: 4z^4/ (25x^6 * y^3 ) **
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RESPONSE --> I moved the 4 to the denominater. self critique assessment: 2
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14:47:54 R.2.122 (was R.4.72). Express 0.00421 in scientific notation.
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RESPONSE --> 4.21*10-3 confidence assessment: 2
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14:48:33 ** 0.00421 in scientific notation is 4.21*10^-3. This is expressed on many calculators as 4.21 E-4. **
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RESPONSE --> ok self critique assessment: 3
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14:49:35 R.2.128 (was R.4.78). Express 9.7 * 10^3 in decimal notation.
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RESPONSE --> 9700 confidence assessment: 2
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14:49:51 ** 9.7*10^3 in decimal notation is 9.7 * 1000 = 9700 **
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RESPONSE --> ok self critique assessment: 3
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15:34:27 R.2.150 (was R.2.78) If an unhealthy temperature is one for which | T - 98.6 | > 1.5, then how do you show that T = 97 and T = 100 are unhealthy?
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RESPONSE --> | T - 98.6 | > 1.5 add 98.6 = T> 100.1 -| T - 98.6 | > 1.5 = ( -T + 98.6) > 1.5 - 98.6 = -t > -97.1 = T < 97.1 T = 97 is unhealthy T = 100 is not unhealthy confidence assessment: 2
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15:36:03 ** You can show that T=97 is unhealthy by substituting 97 for T to get | -1.6| > 1.5, equivalent to the true statement 1.6>1.5. But you can't show that T=100 is unhealthy, when you sustitute for T then it becomes | 100 - 98.6 | > 1.5, or | 1.4 | > 1.5, giving us 1.4>1.5, which is an untrue statement. **
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RESPONSE --> ok self critique assessment: 2
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????wd??O??????assignment #003 003. `query 3 College Algebra 01-21-2007
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15:43:26 R.3.12 (was R.3.6) What is the hypotenuse of a right triangle with legs 14 and 48 and how did you get your result?
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RESPONSE --> A^2 + b^2 = c^2 so 14^2 + 48^2 = x^2 196 + 2304 = 2500 the hypotenuse is 50 confidence assessment: 2
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15:44:09 ** The Pythagorean Theorem tells us that c^2 = a^2 + b^2, where a and b are the legs and c the hypotenuse. Substituting 14 and 48 for a and b we get c^2 = 14^2 + 48^2, so that c^2 = 196 + 2304 or c^2 = 2500. This tells us that c = + sqrt(2500) or -sqrt(2500). Since the length of a side can't be negative we conclude that c = +sqrt(2500) = 50. **
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RESPONSE --> ok self critique assessment: 2
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15:51:27 R.3.18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?
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RESPONSE --> 10 24 26 10^2 + 24^2 = 26^2 100 + 576 = 676 So yrs this is a right triangle confidence assessment: 3
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15:51:44 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **
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RESPONSE --> ok self critique assessment: 2
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16:05:07 R.3.30 (was R.3.24). What are the volume and surface area of a sphere with radius 3 meters, and how did you obtain your result?
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RESPONSE --> v = 4/3)*3.141592654*r^3 so v = 113.097 meters surface area = 4* 3.141592654* r^2 so surface area = 37.70 meters confidence assessment: 2
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16:11:54 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **
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RESPONSE --> Surface Area = 4 * pi * r^2 Got this S = 4 * pi * 3^2 this S = 4 * pi * 9 and even this. S = 36pi m^2. ** why not go on and multiply to get 113.097 m^2 ? self critique assessment: 2
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16:29:13 ** Many students like to use FOIL but it's much better to use the Distributive Law, which will later be applied to longer and more complicated expressions where FOIL does not help a bit. Starting with (-2x - 3) ( 3 - x) apply the Distributive Law to get -2x ( 3 - x) - 3 ( 3 - x). Then apply the Distributive Law again to get -2x(3) - 2x(-x) - 3 * 3 - 3 ( -x) and simiplify to get -6x + 2 x^2 - 9 + 3x. Add like terms to get 2 x^2 - 3 x - 9. **
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RESPONSE --> My dauter just pushed somthing so I will awnser any problem she just put on the screen. sorry find airea of pool + deck then subtract airea of pool 10+3=13 r=13 13^2*Pi = 169* Pi = 530.929 10^2*Pi = 100* Pi = 314.159 530.929 - 314.159 = 216.77 ft^2 or 69*Pi ft^2 005. `query 5 is somehow showing up so i will just ignore it if i am missing somthing just state this in your rsponse thank you. self critique assessment: 2
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course MTH 158 should this be taking so long to finish. around 4 hours per section m???????????assignment #002
......!!!!!!!!...................................
13:40:17 R.2.90 (was R.4.36). Express (x^-2 y) / (x y^2) with only positive exponents and explain how you used the laws of exponents to get your result.
......!!!!!!!!...................................
RESPONSE --> I think this is the place i left off . (x^-2 y) / (x y^2) = (x^-2 / x)*(y / y^2) =(x^-2)^1 (y^1)^2 = x^-1 y^3 This is as far as i could get with the book. my brotherinlaw told me somthing to try so lets see (x^-2 y) / (x y^2) = (x^-2 y) / (x yy) = y / (xxx yy) = 1 / (x^3 y) confidence assessment: 2
.................................................
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13:45:12 ** (1/x^2 * y) / (x * y^2) = (1/x^2 * y) * 1 / (x * y^2) = y * 1 / ( x^2 * x * y^2) = y / (x^3 y^2) = 1 / (x^3 y). Alternatively, or as a check, you could use exponents on term as follows: (x^-2y)/(xy^2) = x^-2 * y * x^-1 * y^-2 = x^(-2 - 1) * y^(1 - 2) = x^-3 y^-1 = 1 / (x^3 y).**
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RESPONSE --> I should have used the law a^-B = 1/a^B bUT I STILL GOT IT self critique assessment: 2
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14:29:18 Extra Problem. . Express 4 x^-2 (y z)^-1 / [ (-5)^2 x^4 y^2 z^-5 ] with only positive exponents and explain how you used the laws of exponents to get your result.
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RESPONSE --> 4 x^-2 (y z)^-1 / [ (-5)^2 x^4 y^2 z^-5 ] =ZZZZZ / 4 XXXXXX YYY Z 25 =Z^4/ 4*X^6*Y^3*25 confidence assessment: 2
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14:31:46 ** Starting with 4x^-2(yz)^-1/ [ (-5)^2 x^4 y^2 z^-5] Squaring the -5 and using the fact that (yz)^-1 = y^1 * z^-1: 4x^-2 * y^-1 * z^-1/ [25 * x^4 * y^2 * z^-5} Grouping the numbers, and the x, the y and the z expression: (4/25) * (x^-2/x^4) * (y^-1/y^2) * (z^-1/z^-5) Simplifying by the laws of exponents: (4/25) * x^(-2-4) * y^(-1-2) * z^(-1+5) Simplifying further: (4/25) * x^-6 * y^-3 * z^4 Writing with positive exponents: 4z^4/ (25x^6 * y^3 ) **
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RESPONSE --> I moved the 4 to the denominater. self critique assessment: 2
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14:47:54 R.2.122 (was R.4.72). Express 0.00421 in scientific notation.
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RESPONSE --> 4.21*10-3 confidence assessment: 2
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14:48:33 ** 0.00421 in scientific notation is 4.21*10^-3. This is expressed on many calculators as 4.21 E-4. **
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RESPONSE --> ok self critique assessment: 3
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14:49:35 R.2.128 (was R.4.78). Express 9.7 * 10^3 in decimal notation.
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RESPONSE --> 9700 confidence assessment: 2
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14:49:51 ** 9.7*10^3 in decimal notation is 9.7 * 1000 = 9700 **
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RESPONSE --> ok self critique assessment: 3
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15:34:27 R.2.150 (was R.2.78) If an unhealthy temperature is one for which | T - 98.6 | > 1.5, then how do you show that T = 97 and T = 100 are unhealthy?
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RESPONSE --> | T - 98.6 | > 1.5 add 98.6 = T> 100.1 -| T - 98.6 | > 1.5 = ( -T + 98.6) > 1.5 - 98.6 = -t > -97.1 = T < 97.1 T = 97 is unhealthy T = 100 is not unhealthy confidence assessment: 2
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15:36:03 ** You can show that T=97 is unhealthy by substituting 97 for T to get | -1.6| > 1.5, equivalent to the true statement 1.6>1.5. But you can't show that T=100 is unhealthy, when you sustitute for T then it becomes | 100 - 98.6 | > 1.5, or | 1.4 | > 1.5, giving us 1.4>1.5, which is an untrue statement. **
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RESPONSE --> ok self critique assessment: 2
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????wd??O??????assignment #003 003. `query 3 College Algebra 01-21-2007
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15:43:26 R.3.12 (was R.3.6) What is the hypotenuse of a right triangle with legs 14 and 48 and how did you get your result?
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RESPONSE --> A^2 + b^2 = c^2 so 14^2 + 48^2 = x^2 196 + 2304 = 2500 the hypotenuse is 50 confidence assessment: 2
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15:44:09 ** The Pythagorean Theorem tells us that c^2 = a^2 + b^2, where a and b are the legs and c the hypotenuse. Substituting 14 and 48 for a and b we get c^2 = 14^2 + 48^2, so that c^2 = 196 + 2304 or c^2 = 2500. This tells us that c = + sqrt(2500) or -sqrt(2500). Since the length of a side can't be negative we conclude that c = +sqrt(2500) = 50. **
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RESPONSE --> ok self critique assessment: 2
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15:51:27 R.3.18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?
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RESPONSE --> 10 24 26 10^2 + 24^2 = 26^2 100 + 576 = 676 So yrs this is a right triangle confidence assessment: 3
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15:51:44 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **
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RESPONSE --> ok self critique assessment: 2
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16:05:07 R.3.30 (was R.3.24). What are the volume and surface area of a sphere with radius 3 meters, and how did you obtain your result?
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RESPONSE --> v = 4/3)*3.141592654*r^3 so v = 113.097 meters surface area = 4* 3.141592654* r^2 so surface area = 37.70 meters confidence assessment: 2
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16:11:54 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **
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RESPONSE --> Surface Area = 4 * pi * r^2 Got this S = 4 * pi * 3^2 this S = 4 * pi * 9 and even this. S = 36pi m^2. ** why not go on and multiply to get 113.097 m^2 ? self critique assessment: 2
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16:29:13 ** Many students like to use FOIL but it's much better to use the Distributive Law, which will later be applied to longer and more complicated expressions where FOIL does not help a bit. Starting with (-2x - 3) ( 3 - x) apply the Distributive Law to get -2x ( 3 - x) - 3 ( 3 - x). Then apply the Distributive Law again to get -2x(3) - 2x(-x) - 3 * 3 - 3 ( -x) and simiplify to get -6x + 2 x^2 - 9 + 3x. Add like terms to get 2 x^2 - 3 x - 9. **
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RESPONSE --> My dauter just pushed somthing so I will awnser any problem she just put on the screen. sorry find airea of pool + deck then subtract airea of pool 10+3=13 r=13 13^2*Pi = 169* Pi = 530.929 10^2*Pi = 100* Pi = 314.159 530.929 - 314.159 = 216.77 ft^2 or 69*Pi ft^2 005. `query 5 is somehow showing up so i will just ignore it if i am missing somthing just state this in your rsponse thank you. self critique assessment: 2
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