course Phy 201
Would like to have feedback. This is the randomized problems assignment under assignment 2.
Problem 1 Version 8If the velocity of the object changes from 3 cm / sec to 11 cm / sec in 9 seconds, then at what average rate is the velocity changing?
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'dv/'dt = averate
11cm/s - 3cm/s = 8cm/s = 'dv
8cm/s / 9s = .89m/(s^2) =average rate
A ball rolling from rest down a constant incline requires 8.6 seconds to roll the 68 centimeter length of the incline.
* What is its average velocity?
vAve = 'ds/'dt
vAve = 68cm/8.6s
vAve = 7.9cm/s
An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.
* What therefore is the final velocity of this ball? vFinal = 2* vAve
vFinal = 2*7.9cm/s = 15.8cm/s
* What average rate is the velocity of the ball therefore changing?
'dv/'dt = averate
averate = 15.8cm/s / 8.6s
averate = 1.84 (cm/s^2)
An automobile accelerates uniformly down a constant incline, starting from rest. It requires 15 seconds to cover a distance of 172 meters. At what average rate is the velocity of the automobile therefore changing?
vAve = 172m/15s
vAve = 11.47m/s
averate = 11.47m/s / 15s
averate = .76m/(s^2)
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This looks good.
Let me know if you have questions.