Random_prblms_assn2

course Phy 201

Problem 1 Version 8If the velocity of the object changes from 3 cm / sec to 11 cm / sec in 9 seconds, then at what average rate is the velocity changing?

'dv/'dt = averate

11cm/s - 3cm/s = 8cm/s = 'dv

8cm/s / 9s = .89m/(s^2) =average rate

A ball rolling from rest down a constant incline requires 8.6 seconds to roll the 68 centimeter length of the incline.

* What is its average velocity?

vAve = 'ds/'dt

vAve = 68cm/8.6s

vAve = 7.9cm/s

An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.

* What therefore is the final velocity of this ball? vFinal = 2* vAve

vFinal = 2*7.9cm/s = 15.8cm/s

* What average rate is the velocity of the ball therefore changing?

'dv/'dt = averate

averate = 15.8cm/s / 8.6s

averate = 1.84 (cm/s^2)

An automobile accelerates uniformly down a constant incline, starting from rest. It requires 15 seconds to cover a distance of 172 meters. At what average rate is the velocity of the automobile therefore changing?

vAve = 172m/15s

vAve = 11.47m/s

averate = 11.47m/s / 15s

averate = .76m/(s^2)

Your first solution is good.

On the last problem you calculated the average velocity correctly. You then divided average velocity by change in clock time.

There is no important calculation that involves dividing average velocity by change in clock time.

Your lines

averate = 11.47m/s / 15s

averate = .76m/(s^2)

are therefore incorrect.

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