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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion:
vAve = 1.25m/s ; vf=2vAve = 2.5m/s; ‘dv=2.5m/s aAve = 2.5m/s/8s=.3m/s^2
vAve = 2m/s; vf= 4m/s; ‘dv = 4m/s; aAve=.8m/s^2
The change in acceleration is .5m/s^ 2. The change in the slope is .05. The rate of change is .1m/s^2.
If you calculated .05 / (.5 m/s^2) you would get .1, but the units would be s^2 / m.
The correct calculation is (change in accel) / (change in slope) = .5 m/s^2 / .05 = 10 m/s^2. This is within 2% of the acceleration of gravity.
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15 mins
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Would like to have feedback. Thanks, Joshua
&#This looks good. See my notes. Let me know if you have any questions. &#