course Mth 163
temp = a(t^2) + b(t) + cxxxx
75 = a(10^2) + b(10) + c
49 = a(30^2) + b(30) + c
30 = a(60^2) + B(60) + C
100a + 10b + c = 75
900a + 30b + c = 49
3600a + 60b + c = 30
3600a + 60b + c = 30
-100a -10b - c = -75
3500a + 50b = -45
3600a + 60b + c = 30
-900a - 30b - c = -49
2700a + 30b = -19
3500a + 50b = -45
2700a + 30b = -19
-3(3500a + 50b) = -3(-45)
5(2700a + 30b) = 5(-19)
-10500a - 150b = 135
13500a + 150b = -95
3000a = 40
a = 0.0133
3500(.0133) + 50b = -45
46.55 + 50b = -45
50b = -92
b = -1.84
2700(.0133) + 30(-1.84) = -19
36 - 55 = -19
a = 0.013, b = -1.84
100(0.013) + 10(-1.84) + c = 75
1.3 - 18.4 + c = 75
c = 92
temp = 0.013 t^2 -1.84t + 92
0 95 92 -3
10 75 75 0
20 60 60 0
30 49 49 0
40 41 39 -2
50 35 33 -2
60 30 30 0
70 26 27 1
Average Deviations -0.75
This was a fairly accurate functioning model
&#Good responses. Let me know if you have questions. &#
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