QA 4

course Mth 163

If your solution to stated problem does not match the given solution, you should self-critique per instructions atvvvv

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of

what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the

given solution.

004.

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Question: `q001. Note that this assignment has 4 questions

If f(x) = x^2 + 4, then find the values of the following: f(3), f(7) and f(-5). Plot the corresponding points on a graph of y = f(x) vs. x. Give a good

description of your graph.

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Your solution:

f(x) = x^2 + 4

f(3), f(7) and f(-5)

f(3) = 3^2 + 4

f(3) = 13

f(7) = 7^2 + 4

f(7) = 53

f(-5) = -5^2 + 4

f(-5) = 29

(3,13) (7, 53) (-5, 29)

parabola

confidence rating:3 OK OK

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Given Solution:

f(x) = x^2 + 4. To find f(3) we replace x by 3 to obtain

f(3) = 3^2 + 4 = 9 + 4 = 13.

Similarly we have

f(7) = 7^2 + 4 = 49 + 4 = 53 and

f(-5) = (-5)^2 + 9 = 25 + 4 = 29.

Graphing f(x) vs. x we will plot the points (3, 13), (7, 53), (-5, 29). The graph of f(x) vs. x will be a parabola passing through these points, since f(x)

is seen to be a quadratic function, with a = 1, b = 0 and c = 4.

The x coordinate of the vertex is seen to be -b/(2 a) = -0/(2*1) = 0. The y coordinate of the vertex will therefore be f(0) = 0 ^ 2 + 4 = 0 + 4 = 4. Moving

along the graph one unit to the right or left of the vertex (0,4) we arrive at the points (1,5) and (-1,5) on the way to the three points we just graphed.

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q002. If f(x) = x^2 + 4, then give the symbolic expression for each of the following: f(a), f(x+2), f(x+h), f(x+h)-f(x) and [ f(x+h) - f(x) ] /

h. Expand and/or simplify these expressions as appropriate.

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Your solution:

f(x) = x^2 + 4

f(a), f(x+2), f(x+h), f(x+h)-f(x) and [ f(x+h) - f(x) ] / h

f(a) = a^2 + 4

f(x+2) = (x + 2)^2 + 4

f(x+2) = (x^2 + 4 x + 4) + 4

f(x+2) = x^2 + 4 x + 8

f(x+h) = (x + h)^2 + 4

f(x+h) = x^2 + 2 h x + h^2 + 4

f(x+h) - f(x) = [ x^2 + 2 h x + h^2 + 4 ] - [ x^2 + 4 ]

f(x+h) - f(x) = x^2 + 2 h x + 4 + h^2 - x^2 - 4

f(x+h) - f(x) = 2 h x + h^2

[ f(x+h) - f(x) ] / h = [ x^2 + 2 h x + h^2 + 4 - ( x^2 + 4) ] / h

[ f(x+h) - f(x) ] / h = (2 h x + h^2) / h

[ f(x+h) - f(x) ] / h = 2 x + h

confidence rating:3 OK OK

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Given Solution:

If f(x) = x^2 + 4, then the expression f(a) is obtained by replacing x with a:

f(a) = a^2 + 4.

Similarly to find f(x+2) we replace x with x + 2:

f(x+2) = (x + 2)^2 + 4, which we might expand to get (x^2 + 4 x + 4) + 4 or x^2 + 4 x + 8.

To find f(x+h) we replace x with x + h to obtain

f(x+h) = (x + h)^2 + 4 = x^2 + 2 h x + h^2 + 4.

To find f(x+h) - f(x) we use the expressions we found for f(x) and f(x+h):

f(x+h) - f(x) = [ x^2 + 2 h x + h^2 + 4 ] - [ x^2 + 4 ] = x^2 + 2 h x + 4 + h^2 - x^2 - 4 = 2 h x + h^2.

To find [ f(x+h) - f(x) ] / h we can use the expressions we just obtained to see that

[ f(x+h) - f(x) ] / h = [ x^2 + 2 h x + h^2 + 4 - ( x^2 + 4) ] / h = (2 h x + h^2) / h = 2 x + h.

You should have written these expressions out, and the following should probably be represented on your paper in form similar to that given here:

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q003. If f(x) = 5x + 7, then give the symbolic expression for each of the following: f(x1), f(x2), [ f(x2) - f(x1) ] / ( x2 - x1 ). Note that

x1 and x2 stand for subscripted variables (x with subscript 1 and x with subscript 2), not for x * 1 and x * 2. x1 and x2 are simply names for two different

values of x. If you aren't clear on what this means please ask the instructor.

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Your solution:

f(x) = 5x + 7

f(x1), f(x2), [ f(x2) - f(x1) ] / ( x2 - x1 )

f(x1) = 5 * x1 + 7

f(x2) = 5 * x2 + 7

[ f(x2) - f(x1) ] / ( x2 - x1) = [ 5 * x2 + 7 - ( 5 * x1 + 7) ] / ( x2 - x1)

[ f(x2) - f(x1) ] / ( x2 - x1) = [ 5 x2 + 7 - 5 x1 - 7 ] / (x2 - x1)

[ f(x2) - f(x1) ] / ( x2 - x1) = (5 x2 - 5 x1) / ( x2 - x1)

[ f(x2) - f(x1) ] / ( x2 - x1) = 5 ( x2 - x1 ) / ( x2 - x1 ) = 5

confidence rating: 3 OK OK

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Given Solution:

Replacing x by the specified quantities we obtain the following:

f(x1) = 5 * x1 + 7,

f(x2) = 5 * x2 + 7,

[ f(x2) - f(x1) ] / ( x2 - x1) = [ 5 * x2 + 7 - ( 5 * x1 + 7) ] / ( x2 - x1) = [ 5 x2 + 7 - 5 x1 - 7 ] / (x2 - x1) = (5 x2 - 5 x1) / ( x2 - x1).

We can factor 5 out of the numerator to obtain

5 ( x2 - x1 ) / ( x2 - x1 ) = 5.

Compare what you have written down with the expressions below:

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q004. If f(x) = 5x + 7, then for what value of x is f(x) equal to -3?

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Your solution:

f(x) = 5x + 7

-3 = 5x + 7

-5x = 10

x = -2

confidence rating: 3 OK OK ............ I thought this was a trick, this is easy stuff.......

A lot of questions are easy if you understand what they're saying, but you'd be surprised how many students can't understand them.

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Given Solution:

If f(x) is equal to -3 then we right f(x) = -3, which we translate into the equation

5x + 7 = -3.

We easily solve this equation (subtract 7 from both sides then divide both sides by 5) to obtain x = -2.

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Self-critique (if necessary):

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Self-critique Rating:

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&#This looks good. See my notes. Let me know if you have any questions. &#