Assignment 15

course mth164

There are 2 submissions before this one. I kept hitting enter instead of tab to go to the next box by mistake. Sorry.

No problem.

?~???????p??V?assignment #015

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015.

Precalculus II

07-17-2007

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08:14:38

Query 10.4.20 (5th ed 10.3.20) solve using determinants -x + 2y = 5, 4x - 8y = 6.

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RESPONSE -->

ok

confidence assessment:

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08:18:20

What is your solution?

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RESPONSE -->

The determinant is zero

The lines are parallel so there is no solution

confidence assessment: 3

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08:20:10

Give the rows, one at a time (i.e., Enter between rows), for the determinant in the numerator of your solution for y, and give the determinant.

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RESPONSE -->

-1 5

4 6

determinant = -26

confidence assessment: 3

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08:20:37

Give the rows, one at a time (i.e., Enter between rows), for the determinant in the denominator of your solution for y, and give the determinant.

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RESPONSE -->

-1 2

4 -8

determinant = 0

confidence assessment: 3

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08:21:41

Query 10.4.30 (5th ed 10.3.30) solve using determinants x - y + z = -4, 2x - 3y + 4z = -15, 5x + y - 2z = 12.

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RESPONSE -->

ok

confidence assessment:

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08:22:28

What is your solution?

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RESPONSE -->

(1, 3, - 2)

confidence assessment: 3

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08:24:02

Give the rows, one at a time (i.e., Enter between rows), for the determinant in the numerator of your solution for z, and give the determinant.

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RESPONSE -->

1 -1 -4

2 -3 -15

5 1 12

Determinant = 10

confidence assessment: 3

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08:26:55

Explain in detail how you evaluated to determinant.

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RESPONSE -->

1 * determinant [[-3,-15],[1,12]] - (-1) * det [[2,-15],[5,12]] + (-4)*det[[2,-3],[5,1]]

confidence assessment: 3

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08:27:43

Give the rows, one at a time (i.e., Enter between rows), for the determinant in the denominator of your solution for z, and give the determinant.

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RESPONSE -->

1 -1 1

2 -3 4

5 1 -2

det=-5

confidence assessment: 3

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08:28:31

Query 10.5.6 (5th ed 10.4.6) A = [ [ 0,3,-5], [1,2,6] ]; B = [ [4,1,0], [-2,3,-2] ], C = [ [4,1], [6,2], [-2,3] ].

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RESPONSE -->

ok

confidence assessment:

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08:30:34

What did you obtain for the expression 2A + 4B?

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RESPONSE -->

2[[0,3,-5],[1,2,6]] + 4[[4,1,0],[-2,3,-2]]=

[[16, 10, -10],[-6, 16, 4]]

confidence assessment: 3

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08:30:59

Query 10.5.10 (5th ed 10.4.10) A = [ [ 0,3,-5], [1,2,6] ]; B = [ [4,1,0], [-2,3,-2] ], C = [ [4,1], [6,2], [-2,3] ].

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RESPONSE -->

ok

confidence assessment:

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08:31:44

What did you obtain for the expression CB?

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RESPONSE -->

[[14, 7, -2],[20, 12, -4],[-14, 7, -6]]

confidence assessment: 3

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08:31:58

Query 10.5.12 (5th ed 10.4.12) A = [ [ 0,3,-5], [1,2,6] ]; B = [ [4,1,0], [-2,3,-2] ], C = [ [4,1], [6,2], [-2,3] ].

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RESPONSE -->

ok

confidence assessment:

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08:33:43

What did you obtain for the expression C(A+B)?

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RESPONSE -->

I added the two matrices together first then multiplied by matrix C and got

[[15, 21, -16],[22, 34, -22],[-11, 7, 22]]

confidence assessment: 3

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08:34:30

Query 10.5.44 (5th ed 10.4.44) solve using inverse matrix x + 2z = 6, -x + 2y + 3z = -5, x - y = 6.

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RESPONSE -->

ok

confidence assessment:

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08:35:11

What is your solution?

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RESPONSE -->

(4, -2, 1)

confidence assessment: 3

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08:36:05

What is your inverse matrix?

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RESPONSE -->

[[3, -2, -4],[3, -2, -5],[-1, 1, 2]]

confidence assessment: 3

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08:36:42

Give the rows, one at a time (i.e., Enter after each row), of the matrix you reduced to obtain the inverse.

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RESPONSE -->

1 0 2

-1 2 3

1 -1 0

confidence assessment: 3

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08:58:17

Give the series of row operations you used to obtain your inverse matrix.

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RESPONSE -->

r1+r2 =r2

r3-r1=r3

gives

1 0 2 | 1 0 0

0 2 5 | 1 1 0

0 -1 -2 | -1 0 1

2r3+r2=r3

1 0 2 | 1 0 0

0 2 5 | 1 1 0

0 0 1 | -1 1 2

-2r3+r1=r1

-5r3+r2=r2

1 0 0 | 3 -2 -4

0 2 0 | 6 -4 -10

0 0 1 | -1 1 2

r2/2=r2

1 0 0 | 3 -2 -4

0 1 0 | 3 -2 -5

0 0 1 | -1 1 2

confidence assessment: 3

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08:58:48

Comm on any surprises or insights you experienced as a result of this assignment.

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RESPONSE -->

Finding the inverse can be tedious and it is so easy to make a mistake since there can be so many row operations to make.

confidence assessment:

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Very good responses. Let me know if you have questions. &#