course phy 201 can u please tell me if this formatted corectly i am trying this on a different pc and it is VERY different in its setup. thank you
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00:52:13 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> First an average or mean of your set of data is found. if you have 6 points then you divide by 5 instead of 6 to find this average. next we must find the square root of this average leaving us with our standard deviation of our set of data. confidence assessment: 2
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00:55:05 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> The largest obstacle in a best fit straight line graph is visualization and no 2 people see the same thing. the equation for a line on a graph is y=mx+b y and x being the corrdinates for each axis, m = slope (rise over run), and b = the vertical intercept. confidence assessment: 2
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01:05:19 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is the action of speed. It is the what and why of moving. I believe it shows a rate because it is an action. confidence assessment: 1
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01:06:04 01-27-2008 01:06:04 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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NOTES -------> ok ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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01:09:43 Given average speed and time interval how do you find distance moved?
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RESPONSE --> you would multiple the speed by the time in order to solve for the distance. confidence assessment: 2
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01:09:58 01-27-2008 01:09:58 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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01:10:05 01-27-2008 01:10:05 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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NOTES -------> ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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01:13:05 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> you would divide the speed by the distance and solve for the time. confidence assessment: 1
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01:13:30 01-27-2008 01:13:30 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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NOTES -------> ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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01:16:29 Given time interval and distance moved how do you get average speed?
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RESPONSE --> ave speed =distance/time confidence assessment: 3
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01:16:46 01-27-2008 01:16:46 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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NOTES -------> ** Average speed = distance / change in clock time. This is the definition of average speed.
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