course phy 201 this is the rework on the homework you requested. ran prob 3 v 4course phy 201 What are the acceleration and final velocity of an object whose average velocity, accelerating uniformly from rest for 7.9 seconds, is 59 cm/s? How far does the object travel during the 7.9 seconds? well since final velocity is double the average velocity so final velocity is 118 cm/sec acceleration is the change in velocity / the change in elasped time so 59 cm/sec / 7.9 sec = 7.5cm For the 7.9 sec interval: What was the initial velocity? &&&& if it is accelerating uniformly from rest then v0=0 What was the final velocity? &&&& meaning the vf=2 * vAve = 2*59cm/s=118cm/s What therefore is the acceleration? &&&& so acceleration is the change in velocty/ the change in elapsed time thus vf-v0 = 118-0=118cm/s tf-t0 = 7.9-0=7.9s 118cm/s/7.9s=14.9cm/s/s