query 5

course phy201

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assignment #005

005. `query 5

Physics I

02-11-2008

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17:30:41

Intro Prob 6 Intro Prob 6 How do you find final velocity and displacement given initial velocity, acceleration and time interval?

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RESPONSE -->

vf=vo+a'dt

'ds=vo'dt+.5a'dt^2

confidence assessment: 3

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17:31:06

** To find final velocity from the given quantities initial velocity, acceleration and `dt:

Multiply `dt by accel to get `dv.

Then add change in velocity `dv to init vel , and you have the final velocity**

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RESPONSE -->

got it

self critique assessment: 2

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17:36:54

Describe the flow diagram we obtain for the situation in which we know v0, vf and `dt.

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RESPONSE -->

aAve = the change in velocity/the change in time

confidence assessment: 0

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17:42:40

** The flow diagram shows us the flow of information, what we get from what, usually by combining two quantites at a time. How we get each quantity may also be included.

From vf and v0 we get `dv, shown by lines from vf and v0 at the top level to `dv. From vf and v0 we also get and vAve, shown by similar lines running from v0 and vf to vAve.

Then from vAve and `dt we get `ds, with the accompanying lines indicating from vAve and `dt to `ds, while from `dv and `dt we get acceleration, indicated similarly. **

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RESPONSE -->

i guess these words make a better picture then the lines i tried to place on the last assignment.

self critique assessment: 1

You did a very good job with the lines. The explanation is probably easier, but maybe not. As I said, you did well with those lines.

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17:46:40

Principles of Physics and General College Physics Students: Prob. 1.26: Estimate how long it would take a runner at 10 km / hr to run from New York to California. Explain your solution thoroughly.

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RESPONSE -->

ok so how about ds=vo'dt+.5a'dt^2

that requires the distance which if i knew how far it was from NY to Ca id implement but i don't, and the acceleration which seems to be a unimform 10km/hr we know our initial velocity is 0 so thats the vo. we can solve therefore for time by isolating it after plugging in the given figures.

confidence assessment: 2

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17:47:20

It is about 3000 miles from coast to coast. A km is about .62 mile, so 3000 miles * 1 km / (.62 miles) = 5000 km, approximately.

At 10 km / hr, the time required would be 5000 km / (10 km / hr) = 500 km / (km/hr) = 500 km * (hr / km) = 500 (km / km) * hr = 500 hr.

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RESPONSE -->

or we could solve it that way

self critique assessment: 1

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Your work looks good. See my notes. Let me know if you have any questions. &#