phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed Question: Asst 2 Question 1
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
My best guess about the balls average velocity is 6 cm/sec. I derived this by subtracting the end velocity from the start velocity and dividing by 2.
(10cm/sec 4 cm/sec) / 2
Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> :
This is a guess because there are more times that could be taken to give a more accurate average. Two times taken, one at the beginning and end of an interval do not reflect the points between that may increase or decrease in velocity.
If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> :
If it takes 3 seconds to get from the first velocity to the second, my best guess about how far it traveled during this time is 18 cm/sec/sec.
We are trying to find the average change in displacement
`d = `v * `t = 6 cm/sec * 3 sec = 18 cm/sec/sec
At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
The average rate of velocity change with respect to clock time during this interval is 6 cm.
Vave = Vf Vo/ `t = (18 cm/s 0 cm/s)/3 sec = 6 cm
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1 hour
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You are working from the definitions, which is good. You're close, but you're not quite applying them correctly.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#