course PHY201

I am not sure if the query assignment is complete - an error (outsideof range) appeared briefly and the program closed. I have attached the send file here.

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assignment #001

001.

Physics I

01-18-2008

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assignment #001

001.

Physics I

01-18-2008

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13:29:24

Explain in your own words how the standard deviation of a set of numbers is calculuated.

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RESPONSE -->

The average of the differences between each data and the set average

confidence assessment: 2

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13:30:36

Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.

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RESPONSE -->

A best-fit line has equal sums of distances to data points above and below it. Performed manually without access to the actual data the results can vary widely.

confidence assessment: 2

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13:31:01

Briefly state what you think velocity is and how you think it is an example of a rate.

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RESPONSE -->

Velocity is how far and object moves in relation to time

confidence assessment: 3

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13:31:10

** A rate is a change in something divided by a change in something else.

This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **

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RESPONSE -->

ok

self critique assessment: 2

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13:31:49

Given average speed and time interval how do you find distance moved?

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RESPONSE -->

d=vt

confidence assessment: 2

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13:31:58

** You multiply average speed * time interval to find distance moved.

For example, 50 miles / hour * 3 hours = 150 miles. **

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RESPONSE -->

ok

self critique assessment: 2

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13:32:51

Given average speed and distance moved how do you find the corresponding time interval?

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RESPONSE -->

t=d/v

confidence assessment: 2

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13:32:58

** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed.

In symbols, if `ds = vAve * `dt then `dt = `ds/vAve.

Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **

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RESPONSE -->

ok

self critique assessment: 2

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13:33:16

Given time interval and distance moved how do you get average speed?

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RESPONSE -->

v=d/t

confidence assessment: 2

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13:33:25

** Average speed = distance / change in clock time. This is the definition of average speed.

For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **

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RESPONSE -->

ok

self critique assessment: 2

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Your work looks good. Let me know if you have any questions. &#