course PHY202
Prof. Smith - Have you received my test #3? I was told it would be faxed but would not be surprised if it were mailed.
I've got both tests. Results should be forthcoming tomorrow.
Using the equations which govern uniformly accelerated motion determine vf, v0, a, s and t for an object which accelerates through a distance of 84 cm, starting from velocity 9 cm/s and accelerating at .375 cm/s/s.
V0 = 9cm/s; vf = 12cm/s; ‘ds = 84cm
vAve = (v0 +vf)/2 = (21cm/s)/2 = 10.5 cm/s
‘dt = ‘ds/’vAve = 84cm/ (10.5 cm/s) = 8s
‘dv = vf – v0 = 3cm/s
aAve = ‘dv/’dt = (3cm/s) / 8s = .375cm/s^2
I doubt this is yours; likely someone submitted it without identification. Either way it's a good solution. If it's not yours it's from someone who is doing well, so no problem either way.