course A ball starting from rest rolls 11 cm down an incline on which its acceleration is 27 cm/s2, then onto a second incline 44 cm long on which its acceleration is 9 cm/s2. How much time does it spend on each incline? A. Vo=0 A= 27cm/s^2 X=11cm Vf=17.23 T=.638s V^2=Vo^2+2ax V^2=0+2(27cm/s^2)(11cm) V^2=297Cm/s^2 Take the square root Vf= 17.23cm/s V=Vo+at 17.23cm/s=0+(27cm/s^2)T Divide by 27 T=.638s B. Vo=17.23cm/s X=44cm A=9cm/s^2 Vf=32.99cm/s T=1.75s V^2=Vo^2+2ax V^2=(17.23cm/s)^2 + 2(9cms^2)(44cm) V^2=296.8729cm^2/s^2+792cm/s Take the square root Vf=32.99cm/s V=Vo+at 32.99cm/s=17.23cm/s+9cm/s^2T Subtract 17.23cm/s from both sides 15.76cm/s=9cm/s^2T Divide by 9 T=1.75s The ball spends .638 seconds on the first incline and 1.75 seconds on the second incline, this is a total of 2.388 seconds on both ramps together.