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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
no, momentum before = .06kg*.8m/s = .048kgm/s
momentum after = .02kg*.7m/s + .06kg*.5m/s = .044kgm/s
• What would the marble velocity have to be in order to exactly conserve momentum?
If the velocities after remain the same, then
.06kg*v = .02kg*.7m/s + .06kg*.5m/s
.06kg*v= .044kg m/s
v = .73m/s
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10 mins
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&#This looks very good. Let me know if you have any questions. &#