Phy 231
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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: 9 sec
What is the velocity at the midpoint of this interval?
answer/question/discussion: 28 cm/s
How far do you think the object travels during this interval?
answer/question/discussion: 252 cm
You need to specify how you result was obtained. It appears to me that you multiply the midpoint clock time by the midpoint velocity. However clock time multiplied by velocity is not an important quantity. Be sure to reason this out based on the definition of average velocity.
By how much does the clock time change during this interval?
answer/question/discussion: 8 sec
By how much does velocity change during this interval?
answer/question/discussion: 24 cm/s
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: 3 cm/s^2
What is the rise of the graph between these points?
answer/question/discussion: 40 – 16 = 24 units
What is the run of the graph between these points?
answer/question/discussion: 13 – 5 = 8
What is the slope of the graph between these points?
answer/question/discussion: 24/8 = 3
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: It gives the rate of acceleration or change of the rate of change
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: 3 cm/s^2
Isn't the 6th question the same question, with a slightly different format, as the last question?
The slope of the v vs. t graph is indeed the same as the average acceleration.
You didn't give enough detail in your calculations. He always need to indicate how the calculation is done. For example the change in velocity would be 40 cm/s - 16 cm/s = 24 cm/s, not just 24 cm/s. Similarly you didn't indicate how you got the 252 cm displacement, but I don't think you did the right thing.
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