Assignment4ver3

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course Phy 201

A bee is making a beeline for its hive. Its velocity is measured at a distance of 75 meters from the observer and again at distance 145 meters from the observer. The clock times at these two positions are t = 9 sec and t = 16 sec, and the measured velocities are 3 m/sec and 13.5 m/sec. What is its average velocity during this time? What is its average acceleration during this time? Is it possible that the acceleration is uniform?

First I drew a picture and then a graph of the problem. The graph is a velocity vs time graph. The velocity portion of the graph has 2 written points on it of 3m/sec and 13.5m/sec. The time portion of the graph has 9sec and 16sec. 2 points on the graph are (9,3) and (16,13.5) . Assuming if the acceleration is linear, then the graph of the line connecting the points is straight.

Next, I solved for average velocity. Avg vel = (3m/sec +13.5m/sec)/2=9.3m/sec.

Avg acceleration = (change in velocity)/(change in time)=(13.5 m/sec-3 m/sec) / (16 sec-9sec)=2.1 m/sec^2

Finally, I would find it hard to believe that the bee travels at a constant acceleration, let alone a straight line. All the numbers are theoretical.

average velocity is (change in position) / (change in clock time).

If acceleration is uniform then average velocity is equal to the average of initial and final velocities.

What do you therefore conclude from the given information?