wk4quiz1ver8

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course Phy 201

A projectile leaves the edge of a table and, while traveling horizontally at a constant 41 cm/s, falls freely a distance of 58 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?According to Newton’s experiments, a ball projected horizontally will reach the ground the same time as a ball being dropped from a free fall. Assuming that the distance to the floor is 58 cm, the v0 should still =0cm/sec

v0=0cm/sec

vf=?

a=980cm/sec^2

‘ds=58cm

vf^2 = v0^2 +2a *’ds

vf^2 = 0 +2 (980cm/sec^2) * 58cm

vf = 337.1cm/sec

vAve = vf/2 = 168.6cm/sec

‘ds = vAve * ’dt

58cm = 168.6cm/sec * ‘dt

‘dt = .34 sec for it to hit the ground

disregarding the air resistance the horizontal motion remains constant.

‘ds = vAve * ‘dt

‘ds = 41cm/sec * .34 sec

‘ds = 13.9cm in the horizontal direction

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wk4quiz1ver8

#$&*

course Phy 201

10/3 1

A projectile leaves the edge of a table and, while traveling horizontally at a constant 41 cm/s, falls freely a distance of 58 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?According to Newton’s experiments, a ball projected horizontally will reach the ground the same time as a ball being dropped from a free fall. Assuming that the distance to the floor is 58 cm, the v0 should still =0cm/sec

v0=0cm/sec

vf=?

a=980cm/sec^2

‘ds=58cm

vf^2 = v0^2 +2a *’ds

vf^2 = 0 +2 (980cm/sec^2) * 58cm

vf = 337.1cm/sec

vAve = vf/2 = 168.6cm/sec

‘ds = vAve * ’dt

58cm = 168.6cm/sec * ‘dt

‘dt = .34 sec for it to hit the ground

disregarding the air resistance the horizontal motion remains constant.

‘ds = vAve * ‘dt

‘ds = 41cm/sec * .34 sec

‘ds = 13.9cm in the horizontal direction

"

just posted; let me know if there's a difference in the documents

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