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course PHY121
Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds66cm/3.8 sec = 17.37cm/s.
vA=(vf+v0)/2
2*vA = vf+v0 2*vA - v0 =vf
2*17.37cm/s - 24cm/s = vf
10.74cm/s = vf
change in velocity is vf - v0 =
10.74cm/s - 24cm/s =dv
-13.26cm/s=dv
The average acceleration is `dv / `dt =
-13.26m/s / 3.8 sec =aA
-3.49m/s2 =aA
&#Your work looks very good. Let me know if you have any questions. &#