phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion:
Mass = m1 + m2
Fnet = mg
Fnet = m1g - m2g
F1 = (5kg* 9.8m/s/s) =49N
F2 = (6 * 9.8 )=58.8N
Fnet = 58.8 - 49 = 9.8N
A = F/m
A = 9.8N / 11kg = .89m/s/s the direction will be towards the heaviest mass
If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion:
V0 = 1.8m/s , vf = 0
A = dv / t = -1.8m/s / 1 s
A = -1.8m/s/s the motion will be slowing down until it reaches the end of the pulley and then it will head in the oppos. direction
During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion:
They are in the same direction , the system slows down as it moves in the negative direction.
velocity and acceleration are in opposite directions, so the system slows; if they were in the same direction the system would speed up.
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20min
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&#This looks good. See my notes. Let me know if you have any questions. &#