phy 201
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Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion:
What are the x and y components of the equilibrant of the force?
answer/question/discussion
Original Force
X = 10cos250 = -3.4
Y = 10sin250 = -9.4
Equilibrant
X = 3.4
Y = 9.4
I checked this by subtracting 180 degrees from 250 to get an angle of 70
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5
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&#Your work looks very good. Let me know if you have any questions. &#