phy201
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion:
A = .3 m/s
R = .2m
M = .110kg
A = v^2/r
A = .3^2m/s/s / .2m
A = .45m/s/s
The acceleration component is pointing away from the force; acting like its trying to escape.
What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion:
F = m (v^2/r)
F = .11kg * .45m/s/s
F = .0495J
The centripetal force holding the ball in orbit is pointed downward away from the ball to keep it in orbit
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10min
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no revision necessary but see the link below for further discussion of the direction of the force
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#
&#Let me know if you have questions. &#