#$&* course mth 277 9/14 11 If your solution to stated problem does not match the given solution, you should self-critique per instructions at
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Let u = <-4,3> and v = <2,-1/2>. Find scalars s and t so that s * <0,3> + tu = v. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: S*<0,3>+t<-4,3>=<2,-1/2> S=2/3 and t=-1/2 confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Let u = 4i - 3j, v = -3i + 4j , and w = 6i - 3j. Write the expression ||u|| ||v|| w in standard form. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: ||u||=sqrt(4^2+(-3)^2)=5 ||v|| =sqrt((-3)^2+4^2)=5 Plug into expression ||u|| ||v|| w =5*5* (6i-3j)= 150i-75j confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Let u = 4i + j, v = 4i + 3j, w = -i + 2j. Find a vector of length 3 with the same direction as u - 2v + 2w. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: (4i+j)-2(4i+3j)+2(-i+2j)=(4-8-2)i+(1-6+4)j= -6i-1j (-6i-1j)/sqrt((-6)^2+(-1)^2)= (-6i-1j)/6.08= -.99i-.16j is the unit vector Then you multiply the unit vector by 3 = 3*(-.99i-.16j)= -2.97i-48j confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Show that the vector v = cos(theta)i + sin(theta)j is a unit vector for any angle theta. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: cos(theta)i + sin(theta)j/sqrt((cos(theta))^2i + (sin(theta))^2j) = cos(theta)i + sin(theta)j/sqrt(1)= cos(theta)i + sin(theta)j/1= cos(theta)i + sin(theta)j The unit vector is cos(theta)i + sin(theta)j because of a identity. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3