#$&* course mth 277 9/14 11 If your solution to stated problem does not match the given solution, you should self-critique per instructions at
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Given Solution: v dot w = 4 * 3 + 1 * 2 = 12 + 2 = 14. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3
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Given Solution: Two vectors are orthogonal if the angle between them is 90 deg, i.e., if and onlye if their dot product is zero. The dot product of these vectors is 5 * 8 - 5 * (-8) + 5 * (-2) = 40 + 40 - 10 = 70. They are not orthogonal. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):you used -8 where it should be -10 ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Find the angle between v = 2i +3 k and w = -j + 4k. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: Use the equation theta = arcCos( A dot B / || A || || B || ) v dot w =2*0+0*-1+3*4=12 || v ||=sqrt(2^2+3^2)=3.6 || w||=sqrt(-1^2+4^2)=4.12 theta = arcCos( 12 / (3.6*4.12) ) = arcos(.81)=35.9 degrees confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: Since v dot w = || v || || w || cos(theta) we have theta = cos^-1 ( v dot w ) || v || || w || = cos^-1 ( 10 / (sqrt(13) * sqrt( 17) ) = cos^-1 (.67) = 48 degrees, approx., or roughly.8 radians. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):I think it was rounding issues ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Find two distinct unit vectors orthogonal to both v = i + 2j -2k and w = i + j - 2k. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: The dot product must equal 0 If you set both equal to zero you get and subtract equation 2 from equation1 (1) i+2j-2k=0 (2) i+j-2k=0 when you subtract them you get j=0 then plug j=0 into both equations you get i+0-2k=0 i+0-2k=0 for both equations you get i=2k both equations are equal to each other so they are perpendicular. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: Suppose a i + b j + c k is orthogonal to both. Then the dot product of this vector with each of the given vectors is zero, and we have a + 2 b - 2 c = 0 a + b - 2 c = 0 Subtracting the second equation from the first we get b = 0. With this value of b both our first and our second equation become a - 2 c = 0 so that a = 2 c. Any vector of the form 2c i + c k is therefore orthogonal to our two vectors. Any such vector has magnitude sqrt( (2 c)^2 + c^2) = sqrt( 5 c^2) = sqrt(5) | c |. If c is positive then | c | = c and our vector is (2 c i + c k ) / (sqrt(5) c) = 2 sqrt(5) / 5 i + sqrt(5) / 5 k. If c is negative then | c | = - c and our vector will be (2 c i + c k ) / (- sqrt(5) c) = - 2 sqrt(5) / 5 i - sqrt(5) / 5 k. Our two solution vectors are equal and opposite. Each is a unit vector perpendicular to the two given vectors. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):I didn’t go into great detail. ------------------------------------------------ Self-critique rating:3
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):okay ------------------------------------------------ Self-critique rating:3 ********************************************* Question: Find the work performed when a force F = (6/11)i - (2/11)j + (6/11)k is applied to an object moving along the line from P(3,5,-4) to Q(-4,-9,-11). YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: pq= (-7i-14j-7k) Fdotpq= (6/11)*-7+(-2/11)*-14+(6/11)*-7=-42/11+28/11-42/11=-56/11 confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: The work is F dot `ds = ( (6/11)i - (2 / 11) j + (6 / 11) k ) dot (-7 i - 14 j - 7 k ) = -42/11 + 28 / 11 - 42 /11 = 28 / 11. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):I think you answer is wrong I have checked my answer multiple times and im getting the same answer. ------------------------------------------------ Self-critique rating:3