course phy201
Determine the acceleration of an object whose velocity is initially 15cm/s and which accelerates uniformly through a distance of 51cm in 4.1 seconds .vAve = Ds/Dt = 51cm/4.1s = 12.439cm/s
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vAve = (vf + vo)/2 = 12.439cm/s*2 -15cm/s = vf = 9.878cm/s
Dv = vf-vo = Dv = 9.878cm/s - 15cm/s = -5.122cm/s
aAve = Dv/Dt = aAve = -5.122cm/s / 4.1s = aAve = -1.249cm/s^2
average acceleration = -1.249cm/s^2
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