course phy201
A projectile leaves the edge of a table and, while traveling horizontally at a constant 41 cm/s, falls freely a distance of 58 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?It will take the projectile .344s to hit the floor. The projectile will also travel 14.11 cm in the horizontal direction during the fall.
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
y=-1/2gt
58cm = -1/2(980cm/s^2)t
58cm = -490cm/s^2(t)
58cm/490cm/s^2 = t
.118367s^2 = t
sqrt.118367s^2 = t
.344s = t
.344s * 41cm/s = 14.11cm (horizontal displacement during fall)"
Good responses. Let me know if you have questions.