Asst 4

course Mth 163

?|????E??????[~?Q?assignment #004

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004.

Precalculus I

06-19-2008

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09:20:20

`questionNumber 40000

`q001. Note that this assignment has 4 questions

If f(x) = x^2 + 4, then find the values of the following: f(3), f(7) and f(-5). Plot the corresponding points on a graph of y = f(x) vs. x. Give a good description of your graph.

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RESPONSE -->

f(3) = 3^2 + 4

f(3) = 13

f(7) = 7^2 + 4

f(7) = 53

f(-5) = -5^2 + 4

f(-5) = 29

The coordinates for the graph would be (3, 13), (7, 53), and (-5, 29). The graph would be a parabola passing through these points. The vertex would be:

-b / 2a = 0 / 2*1 = 0

f(0) = 0 ^2 + 4 = 4. The vertex of the graph would be (0, 4).

The points one unit to the left or right of the vertex would be (1, 5) and (1, -5) and would continue on to the points found earlier.

confidence assessment: 2

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09:20:37

`questionNumber 40000

f(x) = x^2 + 4. To find f(3) we replace x by 3 to obtain

f(3) = 3^2 + 4 = 9 + 4 = 13.

Similarly we have

f(7) = 7^2 + 4 = 49 + 4 = 53 and

f(-5) = (-5)^2 + 9 = 25 + 4 = 29.

Graphing f(x) vs. x we will plot the points (3, 13), (7, 53), (-5, 29). The graph of f(x) vs. x will be a parabola passing through these points, since f(x) is seen to be a quadratic function, with a = 1, b = 0 and c = 4.

The x coordinate of the vertex is seen to be -b/(2 a) = -0/(2*1) = 0. The y coordinate of the vertex will therefore be f(0) = 0 ^ 2 + 4 = 0 + 4 = 4. Moving along the graph one unit to the right or left of the vertex (0,4) we arrive at the points (1,5) and (-1,5) on the way to the three points we just graphed.

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RESPONSE -->

self critique assessment: 3

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09:30:49

`questionNumber 40000

`q002. If f(x) = x^2 + 4, then give the symbolic expression for each of the following: f(a), f(x+2), f(x+h), f(x+h)-f(x) and [ f(x+h) - f(x) ] / h. Expand and/or simplify these expressions as appropriate.

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RESPONSE -->

We just substitute for each value:

f(a) = a^2 + 4

f(x+2) = (x+2)^2 + 4 = (x+2)(x+2) + 4 =

x(x+2)+2(x+2) + 4 =

x^2 + 4x + 8

f(x+h) = (x+h)^2 + 4 = (x+h)(x+h) + 4 =

x^2 + 2xh + h^2 + 4

f(x+h) - f(x) = (x+h)^2 + 4 - f(x) =

x^2 + 2xh + h^2 + 4 - f(x)

[f(x+h) - f(x)] / h = [x^2 + 2xh + h^2 + 4 - f(x)] / h =

x^2 / h + 2x + h + 4/h - f(x)/h

confidence assessment: 2

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09:35:29

06-19-2008 09:35:29

If f(x) = x^2 + 4, then the expression f(a) is obtained by replacing x with a:

f(a) = a^2 + 4.

Similarly to find f(x+2) we replace x with x + 2:

f(x+2) = (x + 2)^2 + 4, which we might expand to get (x^2 + 4 x + 4) + 4 or x^2 + 4 x + 8.

To find f(x+h) we replace x with x + h to obtain

f(x+h) = (x + h)^2 + 4 = x^2 + 2 h x + h^2 + 4.

To find f(x+h) - f(x) we use the expressions we found for f(x) and f(x+h):

f(x+h) - f(x) = [ x^2 + 2 h x + h^2 + 4 ] - [ x^2 + 4 ] = x^2 + 2 h x + 4 + h^2 - x^2 - 4 = 2 h x + h^2.

To find [ f(x+h) - f(x) ] / h we can use the expressions we just obtained to see that

[ f(x+h) - f(x) ] / h = [ x^2 + 2 h x + h^2 + 4 - ( x^2 + 4) ] / h = (2 h x + h^2) / h = 2 x + h.

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NOTES -------> For the last two expression I did not put the expression for f(x) in to solve. Therefore, it looks like I just did a couple steps and stopped before solving the entire function.

Need to remember when it has an expression like f(x+h) - f(x) that I have to substitute for both f(x) values into the expression.

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09:35:30

`questionNumber 40000

If f(x) = x^2 + 4, then the expression f(a) is obtained by replacing x with a:

f(a) = a^2 + 4.

Similarly to find f(x+2) we replace x with x + 2:

f(x+2) = (x + 2)^2 + 4, which we might expand to get (x^2 + 4 x + 4) + 4 or x^2 + 4 x + 8.

To find f(x+h) we replace x with x + h to obtain

f(x+h) = (x + h)^2 + 4 = x^2 + 2 h x + h^2 + 4.

To find f(x+h) - f(x) we use the expressions we found for f(x) and f(x+h):

f(x+h) - f(x) = [ x^2 + 2 h x + h^2 + 4 ] - [ x^2 + 4 ] = x^2 + 2 h x + 4 + h^2 - x^2 - 4 = 2 h x + h^2.

To find [ f(x+h) - f(x) ] / h we can use the expressions we just obtained to see that

[ f(x+h) - f(x) ] / h = [ x^2 + 2 h x + h^2 + 4 - ( x^2 + 4) ] / h = (2 h x + h^2) / h = 2 x + h.

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RESPONSE -->

self critique assessment: 2

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09:45:13

`questionNumber 40000

`q003. If f(x) = 5x + 7, then give the symbolic expression for each of the following: f(x1), f(x2), [ f(x2) - f(x1) ] / ( x2 - x1 ). Note that x1 and x2 stand for subscripted variables (x with subscript 1 and x with subscript 2), not for x * 1 and x * 2. x1 and x2 are simply names for two different values of x. If you aren't clear on what this means please ask the instructor.

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RESPONSE -->

Now we just substitute each expression into f(x) = 5x + 7:

f(x1) = 5x1 + 7

f(x2) = 5x2 + 7

[f(x2) - f(x1)] / (x2 - x1) =

[ 5x2 + 7 - ( 5x1 + 7)] / (x2 - x1) =

( 5x2 - 5x1 ) / (x2 - x1) =

We can factor out 5 and get

5 ( x2 - x1) / (x2 - x1) = 5

confidence assessment: 2

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09:46:00

06-19-2008 09:46:00

Replacing x by the specified quantities we obtain the following:

f(x1) = 5 * x1 + 7,

f(x2) = 5 * x2 + 7,

[ f(x2) - f(x1) ] / ( x2 - x1) = [ 5 * x2 + 7 - ( 5 * x1 + 7) ] / ( x2 - x1) = [ 5 x2 + 7 - 5 x1 - 7 ] / (x2 - x1) = (5 x2 - 5 x1) / ( x2 - x1).

We can factor 5 out of the numerator to obtain

5 ( x2 - x1 ) / ( x2 - x1 ) = 5.

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NOTES -------> I still need to practice the expressions like the third that has all the parts to it.

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09:46:01

`questionNumber 40000

Replacing x by the specified quantities we obtain the following:

f(x1) = 5 * x1 + 7,

f(x2) = 5 * x2 + 7,

[ f(x2) - f(x1) ] / ( x2 - x1) = [ 5 * x2 + 7 - ( 5 * x1 + 7) ] / ( x2 - x1) = [ 5 x2 + 7 - 5 x1 - 7 ] / (x2 - x1) = (5 x2 - 5 x1) / ( x2 - x1).

We can factor 5 out of the numerator to obtain

5 ( x2 - x1 ) / ( x2 - x1 ) = 5.

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RESPONSE -->

self critique assessment: 2

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09:49:02

`questionNumber 40000

`q004. If f(x) = 5x + 7, then for what value of x is f(x) equal to -3?

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RESPONSE -->

If we want to find what value of x is f(x) = -3 we would write the expression like this:

5x + 7 = -3

We would just solve for this function to get the value:

5x + 7 - 7 = -3 - 7

5x = -10

x = -2

confidence assessment: 2

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09:49:31

`questionNumber 40000

If f(x) is equal to -3 then we right f(x) = -3, which we translate into the equation

5x + 7 = -3.

We easily solve this equation (subtract 7 from both sides then divide both sides by 5) to obtain x = -2.

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RESPONSE -->

self critique assessment: 3

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