course Mth 163 assignment #008008.
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14:00:27 `q001. Note that this assignment has 4 questions For the function y = 1.1 x + .8, what are the coordinates of the x = 2 and x = 9 points? What is the rise between these points and what is the run between these points? What therefore is the slope between these points?
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RESPONSE --> For x = 2, y = 1.1*2 + .8 = 2.2 + .8 = 3 For x = 9, y = 1.1*9 + .8 = 9.9 + .8 = 10.7 We have the coordinates (2, 3) and (9, 10.7). The rise between these two point is 10.7 - 3 = 7.7. The run between these two points is 9 - 2 = 7. The slope between these points is 7.7 / 7 = 1.1 confidence assessment: 1
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14:00:51 Evaluating y = 1.1 x +.8 for x = 2 and x = 9 we obtain y = 3 and y = 10.7. The graph points are therefore (2,3) and (9,10.7). The rise between these points is 10.7 - 3 = 7.7 and the run is 9-2 = 7. Thus the slope is 7.7 / 7 = 1.1.
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RESPONSE --> okay self critique assessment: 3
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14:13:47 `q002. For the function y = 1.1 x + .8, what are the coordinates of the x = a point, in terms of the symbol a? What are the coordinates of the x = b point, in terms of the symbol b?
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RESPONSE --> I'm not sure about the a point, but I do know that the function is y = mx + b, so b = .8. To solve for the coordinates, if x = b we find: y = 1.1*.8 + .8 = .88 + .8 = 1.68 (.8, 1.68) Or is the correct way of finding the coordinates doing: y = 1.1*a + .8 confidence assessment: 0
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14:15:15 If x = a, then y = 1.1 x + .8 gives us y = 1.1 a + .8. If x = b, then y = 1.1 x + .8 gives us y = 1.1 b + .8. Thus the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8).
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RESPONSE --> I made it harder than it really was. self critique assessment: 3
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14:17:59 `q003. We see that the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8). What therefore is the rise between these two points? What is the run between these two points?
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RESPONSE --> The rise between the two coordinates would be: (1.1b + .8) - (1.1a + .8) = 1.1b - 1.1a The run between the two coordinates would be: (b - a) confidence assessment: 1
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14:18:38 The rise between the points is the rise from y = 1.1 a + .8 to y = 1.1 b + .8, a rise of rise = (1.1 b + .8) -(1.1 a + .8) = 1.1 b + .8 - 1.1 a - .8 = 1.1 b - 1.1 a. The run is from x = a to x = b, a run of run = b - a.
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RESPONSE --> I came to the same answer self critique assessment: 3
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14:20:59 `q004. We see that the rise between the x = a and x = b points of the graph of y = 1.1x +.8 is 1.1 b + .8 - (1.1 a + .8), while the run is b - a. What therefore is the average slope of the graph between these points? Simplify your answer.
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RESPONSE --> I believe the slope would be: [(1.1b + .8) - (1.1a + .8)] / b - a = (1.1b - 1.1a) / b - a = 0 confidence assessment: 0
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14:25:16 The slope is slope = rise / run = (1.1 b - 1.1 a) / (b - a) = 1.1 (b - a) / (b - a) = 1.1. The significance of this series of exercises is that the slope between any two points of the straight line y = 1.1 x + .8 must be 1.1, no matter whether the points are given by numbers (e.g., x = 2 and x = 9) or by symbols (x = a and x = b). Mostly
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RESPONSE --> I wasn't sure about finding the slope of that type of function. I see why it is 1.1 instead of 0, I was suppose to divide it first before subtracting. self critique assessment: 2
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Ș~ѳۮJе̕ assignment #008 008. `query 8 DERIVE exercise, Major Quiz ... Precalculus I 07-15-2008
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10:04:34 Were you able to complete the DERIVE exercise?
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RESPONSE --> I was not able to locate the trial on the TI web page for the DERIVE program, therefore I wasn't able to complete the exercise. confidence assessment: 1
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10:06:06 Did you understand everything in the DERIVE exercise?
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RESPONSE --> After reading what was to be done in the DERIVE exercise I see how the system is to be used and how it can help with equations and graphs. confidence assessment: 1
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10:06:14 Do you have any questions about the DERIVE exercise?
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RESPONSE --> no confidence assessment: 1
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