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Phy 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
d=v0*t+1/2*a*t^2
2m= ½*a*(0.64s)^2
2m=1/2*a*0.4096s^2
4m=a*0.4096s^2
a=9.8m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
d=v0*t+1/2*a*t^2
5m = 0*1.05s + ½*a*(1.05s)^2
5m= ½*a*1.103s^2
10m = a*1.103s^2
a= 9.08m/s^2
This value is close but not consistent with the first acceleration value.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The first answer is the same but the second answer is off by 0.72 units.
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15min
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&#This looks very good. Let me know if you have any questions. &#