cq_1_111

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Phy 201

Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Answer the following based on Newton's Second Law:

• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?

answer/question/discussion: ->->->->->->->->->->->-> :

Fnet= m*a = 12kg* 3m/s^2 = 36kg*m/s^2

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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?

answer/question/discussion: ->->->->->->->->->->->-> :

Fnet = m*a

a= Fnet/m

a= 20kg*m/s^2 / 4kg = 5m/s^2

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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?

answer/question/discussion: ->->->->->->->->->->->-> :

This is because Fnet= m*a, therefore if you use these variables to find the Fnet you realize that the given Fnet of 20 Newtons is not equal to the calculated Fnet of 15 Newtons (1.5m/s^2 * 10kg) which means that there is 5 Newtons of other forces acting on the system (20Newtons- 15Newtons).

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• What is the total of all those forces and in what direction does this total act?

answer/question/discussion: ->->->->->->->->->->->-> :

The other forces sum up to be 5 Newtons and they are acting in the direction of your force since the outcome is a positive force in the direction you are pushing.

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10min

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&#Very good responses. Let me know if you have questions. &#