asst 3

Let me know if this isn't yours. It was submitted in sequence with other assignments of yours, and it sound like you (that's a good thing).

Mr. Smith please dont think that I have quite on you! My brother got married this weekend so I was busy decorating the church and I had to take care of my neice this week because my grandmother had to go to Baltimore to have surgery and my mom had to go with her so I was stuck with the baby this whole time up until now. I will try to get a lot of work done this week. Thanks ? ??E~???L?????assignment #003

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

{???H??y?????? Applied Calculus I 06-15-2006

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09:36:32 0.3.24 (was 0.3.24 simplify z^-3 (3z^4)

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RESPONSE --> 3 * z ^ -3+4= 3z

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09:37:11 ** z^-3 ( 3 z^4) = 3 * z^-3 * z^4 = 3 * z^(4-3) = 3 z. **

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RESPONSE --> I need to be showing more steps. I just did it all at once.

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09:39:31 0.3.30 (was 0.3.30 simplify(12 s^2 / (9s) ) ^ 3

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RESPONSE --> (12s/9)^3= 12s^3/729= 4s^3/243

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09:41:03 ** Starting with (12 s^2 / (9s) ) ^ 3 we simplify inside parentheses to get ( 4 s / 3) ^ 3, which is equal to 4^3 * s^3 / 3^3 = 64 s^3 / 27 It is possible to expand the cube without first simplifying inside, but the subsequent simplification is a little more messy and error-prone; however done correctly it gives the same result. It's best to simplify inside the parentheses first. **

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RESPONSE --> I thought for some reason that I didnt have to cube the 12 .....I just cubed the s and not the 12 .....so that is were I messed up

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09:46:35 0.3.38 (was 0.3.38 simplify ( (3x^2 y^3)^4) ^ (1/3) and (54 x^7) ^ (1/3)

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RESPONSE --> I think that you may have wrote the first one wrong because the one in the book is ((3x^2 y^3)^4) ^ (1/4) ......When you multiply 4 by 1/4 you get one so you end up with just (3x^2 y^3) 54= 2*3*3*3-= 2* 3^3 (2*3^3*x^7)^(1/3) 3^3^1/3=3 x^6^1/3= x^2 3*x^2*2x^(1/3)

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09:46:54 ** To simplify (54 x^7)^(1/3) you have to find the maximum factor inside the parentheses which a perfect 3d power. First factor 54 into its prime factors: 54 = 2 * 27 = 2 * 3 * 3 * 3 = 2 * 3^3. Now we have (2 * 3^3 * x^7)^(1/3). 3^3 and x^6 are both perfect 3d Powers. So we factor 3^3 * x^6 out of the expression in parentheses to get ( (3^3 * x^6) * 2x ) ^(1/3). This is equal to (3^3 * x^6)^(1/3) * (2x)^(1/3). Simplifying the perfect cube we end up with 3 x^2 ( 2x ) ^ (1/3) For the second expression: The largest cube contained in 54 is 3^3 = 27 and the largest cube contained in x^7 is x^6. Thus you factor out what's left, which is 2x. Factoring 2x out of (54 x^7)^(1/3) gives you 2x ( 27 x^6) so your expression becomes [ 2x ( 27 x^6) ] ^(1/3) = (2x)^(1/3) * [ 27 x^6 ] ^(1/3) = (2x)^(1/3) * [ (27)^(1/3) (x^6)^(1/3) ] = (2x)^(1/3) * 3 x^2, which in more traditional order is 3 x^2 ( 2x)^(1/3). **

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RESPONSE --> I understand

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09:49:25 0.3.58 (was 0.3.54 factor P(1+r) from expression P(1+r) + P(1+r)^2 + P(1+r)^3 + ...

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RESPONSE --> p(1+r)/everything up to n 1+(1+r)+(1+r)^2+...+(1+r)^n

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09:50:14 ** Few students get this one. If you didn't you've got a lot of company; if you did congratulations. It's important to understand how this problem illustrates the essence of factoring. It's important also because expressions of this form occur throughout calculus. Factor out P * (1 + r). Divide each term by P ( 1 + r), and your result is P (1 + r) * your quotient. Your quotient would be 1 + (1+r) + (1+r)^2 + (1+r)^3 + ... . The factored form would therefore be P(1+r) [ 1 + (1+r) + (1+r)^2 + (1+r)^3 + ... ]. You can verify that this is identical to the original expression if you multiply it back out. Analogy with different exponents and only three terms: A x^3 + A x^4 + A x^5 can be divided by A x^2 to give quotient x + x^2 + x^3, so the factored expression is A ( x + x^2 + x^3). **

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RESPONSE --> Wow.....I am surprised....

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Good. Let me know if you have questions.