Query 8

course Mth 271

????|???????assignment #008{???H??y??????

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Applied Calculus I

07-03-2006

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18:11:38

What functions f(z) and g(t) express the function 2^(3t-5) as a composite f(g(t))?

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RESPONSE -->

Wow! .......These really get me! .... F(z)= 2^z and g(t) = (3t-5) .....I think that I could say this but I am not sure ao the G(t)..... f(g(t))= 2^z ...z= 2^3t-5 .....if this is right then I think I lost my t but this is the only thing I can come up with for this one

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18:12:13

CORRECT STUDENT RESPONSE: f(z)=2^z and g(t)=3t-5, so that f(g(t)) = 2^g(t) = 2^(3t-5).

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I actually got this right....but I am still very unsure about this ....lucky guess!

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18:12:28

19:11:56

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RESPONSE -->

I am not sure about this???

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18:13:11

1.3.81 (was 1.3.66 temperature conversion

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RESPONSE -->

212- 32 / 100 -0 = 1.8

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18:13:49

What linear equation relates Celsius to Fahrenheit?

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RESPONSE -->

y= mx + b

F=C 1.8+ 32

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18:14:03

CORRECT STUDENT RESPONSE: degrees Fahrenheit=1.8(degrees Celsius)+32, or F = 1.8 C + 32.

INSTRUCTOR COMMENT:

Since each Fahrenheit degree is 1.8 Celsius degrees a graph of F vs. C will have slope 1.8. Since F = 32 when C = 0 the graph will have vertical intercept at (0, 32) so the y = m x + b form will be F = 1.8 C + 32.

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RESPONSE -->

I understand how to do this

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18:15:22

How did you use the boiling and freezing point temperatures to get your relationship?

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RESPONSE -->

I used them like slope so F boiling pt. - F freezing pt. / c boiling pt - C frezzing pt.

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18:15:34

** A graph of Fahrenheit vs. Celsius temperatures gives us the two (x,y) points (o,32) and (100,212).

We use these two points to find the slope m=(y2-y1)/(x2-x1) = (212 - 32) / 100 = 1.8.

Now we insert the coordinates of the point (0,32) and into the point-slope form y = 1.8 x + b of a line to get 32 = 1.8 * 0 + b. We easily solve to get b = 32.

{So the equation is y = 1.8 x + 32, or F = 1.8 C + 32. **

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RESPONSE -->

I understnad this

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"

Good. Let me know if you have questions.