course Mth 271 ????|???????assignment #008{???H??y??????
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18:11:38 What functions f(z) and g(t) express the function 2^(3t-5) as a composite f(g(t))?
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RESPONSE --> Wow! .......These really get me! .... F(z)= 2^z and g(t) = (3t-5) .....I think that I could say this but I am not sure ao the G(t)..... f(g(t))= 2^z ...z= 2^3t-5 .....if this is right then I think I lost my t but this is the only thing I can come up with for this one
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18:12:13 CORRECT STUDENT RESPONSE: f(z)=2^z and g(t)=3t-5, so that f(g(t)) = 2^g(t) = 2^(3t-5).
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RESPONSE --> I actually got this right....but I am still very unsure about this ....lucky guess!
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18:12:28 19:11:56
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RESPONSE --> I am not sure about this???
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18:13:11 1.3.81 (was 1.3.66 temperature conversion
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RESPONSE --> 212- 32 / 100 -0 = 1.8
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18:13:49 What linear equation relates Celsius to Fahrenheit?
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RESPONSE --> y= mx + b F=C 1.8+ 32
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18:14:03 CORRECT STUDENT RESPONSE: degrees Fahrenheit=1.8(degrees Celsius)+32, or F = 1.8 C + 32. INSTRUCTOR COMMENT: Since each Fahrenheit degree is 1.8 Celsius degrees a graph of F vs. C will have slope 1.8. Since F = 32 when C = 0 the graph will have vertical intercept at (0, 32) so the y = m x + b form will be F = 1.8 C + 32.
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RESPONSE --> I understand how to do this
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18:15:22 How did you use the boiling and freezing point temperatures to get your relationship?
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RESPONSE --> I used them like slope so F boiling pt. - F freezing pt. / c boiling pt - C frezzing pt.
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18:15:34 ** A graph of Fahrenheit vs. Celsius temperatures gives us the two (x,y) points (o,32) and (100,212). We use these two points to find the slope m=(y2-y1)/(x2-x1) = (212 - 32) / 100 = 1.8. Now we insert the coordinates of the point (0,32) and into the point-slope form y = 1.8 x + b of a line to get 32 = 1.8 * 0 + b. We easily solve to get b = 32. {So the equation is y = 1.8 x + 32, or F = 1.8 C + 32. **
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RESPONSE --> I understnad this
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