Phy 121
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
To determine the velocity after the 3 seconds elapsed, I took the acceleration rate and multiplied it by the time elapsed. 8 cm/s^2 * 3 seconds = 24 cm/s^3
cm/s^2 * s = (cm / s^2) * (s / 1) = (cm * s) / (s^2) = cm / s.
Note also that cm/s^3 is not a unit of velocity.
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Assuming that the acceleration is constant, then the average velocity is 18 cm/s^3. I determined this by adding the two velocities and dividing by 2. 24 cm/s^3 + 12 cm/s = 36 cm/s^3 / 2 = 18 cm/s^3.
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
During this interval, they object travels 12 cm/s^3. We determine this by taking our final velocity and subtracting our first velocity to give us a change in position. This gives us 24 cm/s^3 – 12cm/s = 12 cm/s^3
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30-40
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Good work, but you need to fix those units.
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Solution
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