Phy 121
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Based on the given information, we assume that v0=0 and vf= 2 m. Our time period is .64 seconds. To determine acceleration we divide ‘dv/’dt. This gives us 3.12m/s
0 and 2 m are positions, not velocities.
What you have calculated is the average rate of change of position with respect to clock time, or average velocity. You still need to find the acceleration.
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
Based on the given information, we assume that v0=0 and vf= 5. Our time period is 1.05 s. To determine acceleration we divide ‘dv/’dt. This gives us 4.76m/s
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
These observations are not consistent with the accepted value of acceleration of gravity. I read through the book on acceleration of falling objects and it showed several formulas using a= 9.8 m/s^2. Is this something we will focus on later, or was this to be somehow incorporated into the problems on this seed question???
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30 minutes
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Solution
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