Phy 121
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
I think this means that the triangle would need to be rotated so that the triangle would be in what is known as quadrant II ( at least I think it is quadrant II).
#$&*
Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
I think that I would perceive it as going backwards since the angle would be open and heading in the reverse direction. I think that this component is in the direction of motion
#$&*
Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
I think the object will speed up at a constant rate.
#$&*
If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
I think that the component of the force perpendicular to the line of motion will be directed to the left. I think this is the direction that the motion will move in.
#$&*
Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
I think the object may veer off slightly to whichever side had the longest triangle leg, I think it would be in this direction because that angle would have the most force being exerted on it. I think that it will veer off slightly to the left.
#$&*
Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
Arent these forces equal and opposite to one another???
#$&*
** **
35-40 minutes
** **
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#