phy 121
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
5/16 11
** **
35 minutes
** **
A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
• What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
When this says weight, does it mean what is the force of the ball???
If so, we would figure out the force as follows: F = m*a.
F= .4 kg * 9.8 m/s^2
F = 3.92 Newtons
#$&*
• What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
If we know our tension force and the force from the ball we can determine the buoyant force. We set this up as follows : -3.92N + Buoyant Force+ 2.5 Newtons = 0
-1.42Newtons+Buoyant force = 0
So our buoyant force is a + 1.42 Newtons.
#$&*
• What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
1.42 Newtons = m*9.8m/s^2
To get mass by itself, we divide each side by 9.8 m/s^2. when we do this, it gives us a mass of .145 kg. This is equivalent to 145 grams.
#$&*
• What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
If our mass is 145 grams then it means that the density of the object is 145 cm^3 since 1 g is equal to 1 cm^3.
#$&*
Good start. A little confusion on the details of the last couple of questions, but I think you'll get that completely straight by reading the discussion. Let me know if not.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#