Query Assignment 19

course Phy 121

iץʠȓI汝bassignment #019

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019. `query 19

Physics I

03-03-2008

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01:03:45

** STUDENT RESPONSE:

x component of the vector = magnitude * cos of the angle

y component of the vector = magnitude * sin of the angle

To get the magnitude and angle from components:

angle = arctan( y component / x component ); if the x component is less than 0 than we add 180 deg to the solution

To get the magnitude we take the `sqrt of ( x component^2 + y component^2) **

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RESPONSE -->

x component of the vector = magnitude * cos of the angle

y component of the vector = magnitude * sin of the angle

To get the magnitude and angle from components:

angle = arctan( y component / x component ); if the x component is less than 0 than we add 180 deg to the solution

To get the magnitude we take the `sqrt of ( x component^2 + y component^2)

self critique assessment: 2

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01:04:47

** If one person pulls with the given force F in the given direction the effect is identical to what would happen if two people pulled, one in the x direction with force Fx and the other in the y direction with force Fy. **

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RESPONSE -->

If one person pulls with the given force F in the given direction the effect is identical to what would happen if two people pulled, one in the x direction with force Fx and the other in the y direction with force Fy.

self critique assessment: 1

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01:08:01

Explain how we can calculate the magnitude and direction of the velocity of a projectile at a given point.

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RESPONSE -->

By using the x and y coordinates you can find the angle of the point from the origin. At that point you can multiply the x by tangent and y by tangent to give you a certain direction. At that point we can use the direct to understand the velocity.

confidence assessment: 1

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01:08:22

** Using initial conditions and the equations of motion we can determine the x and y velocities vx and vy at a given point, using the usual procedures for projectiles.

The magnitude of the velocity is sqrt(vx^2 + vy^2) and the angle with the pos x axis is arctan(vy / vx), plus 180 deg if x is negative. **

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RESPONSE -->

Using initial conditions and the equations of motion we can determine the x and y velocities vx and vy at a given point, using the usual procedures for projectiles.

The magnitude of the velocity is sqrt(vx^2 + vy^2) and the angle with the pos x axis is arctan(vy / vx), plus 180 deg if x is negative.

self critique assessment: 3

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01:08:50

** Initial vel in the x direction is v cos(theta), where v and theta are the magnitude and the angle with respect to the positive x axis.

Initial vel in the y direction is v sin(theta). **

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RESPONSE -->

Initial vel in the x direction is v cos(theta), where v and theta are the magnitude and the angle with respect to the positive x axis.

Initial vel in the y direction is v sin(theta).

self critique assessment: 2

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Let me know if there's anything you need me to clarify.