Find the distance between the points... (-9,3) and (0,0) ....is that just the slope?...thanks..
The distance could be found from the run and the slope, or from the rise and the slope, but it's not the same thing as the slope and we don't really want to use the slope to find the distance.
However you use the same triangle you use when calculating the slope. This triangle is a right triangle whose legs are equal to the magnitudes of the run and the rise. The distance between the points is the hypotenuse.
For these points, the 'run' is 9 and the 'rise' is -3. So the legs are 9 and 3.
By the Pythagorean Theorem, then, we have
c^2 = a^2 + b^2, where a = 9 and b = 3. So
c^2 = 9^2 + 3^2 = 81 + 9 = 90 and
c = sqrt(90) = 3 sqrt(10), or approximately 9.4.
The distance between the points is 3 sqrt(10) (exact) or 9.4 ( approximate).
Find the distance between the points... (-9,3) and (0,0) ....is that just the slope?...thanks..
The distance could be found from the run and the slope, or from the rise and the slope, but it's not the same thing as the slope and we don't really want to use the slope to find the distance.
However you use the same triangle you use when calculating the slope. This triangle is a right triangle whose legs are equal to the magnitudes of the run and the rise. The distance between the points is the hypotenuse.
For these points, the 'run' is 9 and the 'rise' is -3. So the legs are 9 and 3.
By the Pythagorean Theorem, then, we have
c^2 = a^2 + b^2, where a = 9 and b = 3. So
c^2 = 9^2 + 3^2 = 81 + 9 = 90 and
c = sqrt(90) = 3 sqrt(10), or approximately 9.4.
The distance between the points is 3 sqrt(10) (exact) or 9.4 ( approximate).