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phy 231
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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
400 g = .4 kg, .4 kg*9.8 m/s/s = 3.92 N
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What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball’s weight of 3.92 N is pulling downward; the chain is pulling upward at 2.5 N. The Fnet = 3.92 N - 2.5 N = 1.42 N. The buoyant force to keep it afloat must then be 1.42 N
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What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
Archimedes Principle: buoyant force = weight of the water it displaces
Therefore the water must weigh 1.42 N. Water’s has mass of 1000 kg/m^3, to find its weight * 9.8 m/s/s = 9800 N/m^3
If density = mass/volume, then volume = mass/density = 1.42N/9800N/m^3 = .000145 m^3.
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What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
density = .4 kg/.000145 m^3 = 2758.6 kg/m^3
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