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Phy 231
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = 1/2a`dt^2 + V0`dt
A = 2`ds/`dt^2
A = 2(2m) / (.64s)^2
A = 9.76m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = 1/2a`dt^2 + V0`dt
A = 2`ds/`dt^2
A = 2(5m) / (1.05s)^2
A= 9.07m/s^2
No, the accelerations are different.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
No, the accelerations are different than gravity. This is most likely due to error in data collection or resistance.
@& If the accuracy of the experiment that determines the values results in, say, a 10% uncertainty, then the results would be consistent. With highly accurate instruments, used properly, these results would not be consistent.*@
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7 minutes
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&#Good responses. See my notes and let me know if you have questions. &#