course Phy 201 out in the multiplying.confidence assessment: 3
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00:05:19 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> Ok self critique assessment: 3
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00:06:47 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Divide the average speed by the distance moved. Example: 60mph/60 m=1 hour. confidence assessment: 3
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00:07:59 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> OK self critique assessment: 3
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00:09:37 Given time interval and distance moved how do you get average speed?
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RESPONSE --> Distance traveled divided by time interval. Example: 60 miles in 1 hour = (60miles/1hour)=60mph confidence assessment: 3
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00:09:48 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> OK self critique assessment: 3
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