question form

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Mth 164

Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** Question Form_labelMessages **

Assignment 2 Question

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The problem can be found:

In the video notes of Assignment 2,

Located in the folder named disk 1

then the folder 990118

there is the picture pc10 (Also at the end of the video Snazzi2)

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We are looking at the unit circle with the angle of pi'/3 (60 degrees)

Using the Pythagorean theory to solve for the location of the y value of pi' /3. I understand the following and how we acquired it:

'sqrt(1/2 A)^2 + y^2) = 'sqrt(A^2)

Although, I don't understand how we came to this solution:

The given solution of y = ('sqrt 3) / 2

Specifically where the 'sqrt 3 came from.

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Could you show me the steps to reach the following solution to the following question:

Question: 'sqrt(1/2 A)^2 + y^2) = 'sqrt(A^2)

Soultion: y = ('sqrt 3) / 2

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Square both sides to get

1/4 A^2 + y^2 = A^2

Subtract 1/2 A^2 from both sides to get

y^2 = 3/4 A^2.

Solve to get

| y | = sqrt(3) / sqrt(4) * A, or sqrt(3) / 2 * A.

The positive value of y is the one that works for 60 degrees.

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Let me know if you have additional questions. This is important.

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