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Mth 164
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
Assignment 2 Question
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The problem can be found:
In the video notes of Assignment 2,
Located in the folder named disk 1
then the folder 990118
there is the picture pc10 (Also at the end of the video Snazzi2)
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We are looking at the unit circle with the angle of pi'/3 (60 degrees)
Using the Pythagorean theory to solve for the location of the y value of pi' /3. I understand the following and how we acquired it:
'sqrt(1/2 A)^2 + y^2) = 'sqrt(A^2)
Although, I don't understand how we came to this solution:
The given solution of y = ('sqrt 3) / 2
Specifically where the 'sqrt 3 came from.
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Could you show me the steps to reach the following solution to the following question:
Question: 'sqrt(1/2 A)^2 + y^2) = 'sqrt(A^2)
Soultion: y = ('sqrt 3) / 2
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Square both sides to get
1/4 A^2 + y^2 = A^2
Subtract 1/2 A^2 from both sides to get
y^2 = 3/4 A^2.
Solve to get
| y | = sqrt(3) / sqrt(4) * A, or sqrt(3) / 2 * A.
The positive value of y is the one that works for 60 degrees.
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Let me know if you have additional questions. This is important.
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